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Question: Determine the ratio in which line \( 2x + y - 4 = 0 \) divides the line segment joining the points \...

Determine the ratio in which line 2x+y4=02x + y - 4 = 0 divides the line segment joining the points A(2,2)andB(3,7)A\left( {2, - 2} \right)\,\,and\,\,B\left( {3,7} \right)

Explanation

Solution

Hint : For this we first let the ratio be k:1k:1 then using section formula we first find coordinates of the point which is common on a given line segment and on a given line. Then substituting these coordinates in the given equation of a line to find the value of k or required ratio.
Formulas used: Section formula: x=mx2+nx1m+n,y=my2+ny1m+nx = \dfrac{{m{x_2} + n{x_1}}}{{m + n}},\,\,y = \dfrac{{m{y_2} + n{y_1}}}{{m + n}}

Complete step-by-step answer :
Let the ratio be k:1k:1 in which given line 2x+y4=02x + y - 4 = 0 divides the line segment joining the points
A(2,2)andB(3,7)A\left( {2, - 2} \right)\,\,and\,\,B\left( {3,7} \right) .

Then, by using the section formula we can find the coordinate of the point which divides the line segment joining the points A(2,2)andB(3,7)A\left( {2, - 2} \right)\,\,and\,\,B\left( {3,7} \right) .
Therefore, we have:
x=3k+2k+1,y=7k2k+1x = \dfrac{{3k + 2}}{{k + 1}},\,\,y = \dfrac{{7k - 2}}{{k + 1}}
Since, this point is common on line segment joining points A(2,2)andB(3,7)A\left( {2, - 2} \right)\,\,and\,\,B\left( {3,7} \right) and line 2x+y4=02x + y - 4 = 0 .
Therefore, substituting the value of ‘x’ and ‘y’ in the given equation and simplifying to get the value of k.
2(3k+2k+1)+(7k2k+1)4=0 6k+4k+1+7k2k+14=0  2\left( {\dfrac{{3k + 2}}{{k + 1}}} \right) + \left( {\dfrac{{7k - 2}}{{k + 1}}} \right) - 4 = 0 \\\ \Rightarrow \dfrac{{6k + 4}}{{k + 1}} + \dfrac{{7k - 2}}{{k + 1}} - 4 = 0 \\\
takingLCM 6k+4+7k24(k+1)k+1=0  taking\,\,LCM \\\ \dfrac{{6k + 4 + 7k - 2 - 4\left( {k + 1} \right)}}{{k + 1}} = 0 \\\

13k+24k4k+1=0 9k2k+1=0 9k2=0 9k=2 k=29   \Rightarrow \dfrac{{13k + 2 - 4k - 4}}{{k + 1}} = 0 \\\ \Rightarrow \dfrac{{9k - 2}}{{k + 1}} = 0 \\\ \Rightarrow 9k - 2 = 0 \\\ \Rightarrow 9k = 2 \\\ \Rightarrow k = \dfrac{2}{9} \;
Therefore, from above we can see that the value of k is 29\dfrac{2}{9} or we can say that ratio is 29\dfrac{2}{9} .
Hence, we see that line 2x+y4=02x + y - 4 = 0 divides line segment joining points A(2,2)andB(3,7)A\left( {2, - 2} \right)\,\,and\,\,B\left( {3,7} \right) in ratio 29\dfrac{2}{9} .
So, the correct answer is “ 29\dfrac{2}{9}”.

Note : For this type of problem we can either take the ratio as in terms of a:ba:b and then use the section formula to find coordinates of the points which lie on both line segments joining given points and on a given line. Then substituting the coordinate of this point in the given line to form an equation in terms of a and b then finding the value of ab\dfrac{a}{b} by dividing the whole equation by b and hence required ratio asked in the given problem.