Question
Question: Determine the ratio in which line \( 2x + y - 4 = 0 \) divides the line segment joining the points \...
Determine the ratio in which line 2x+y−4=0 divides the line segment joining the points A(2,−2)andB(3,7)
Solution
Hint : For this we first let the ratio be k:1 then using section formula we first find coordinates of the point which is common on a given line segment and on a given line. Then substituting these coordinates in the given equation of a line to find the value of k or required ratio.
Formulas used: Section formula: x=m+nmx2+nx1,y=m+nmy2+ny1
Complete step-by-step answer :
Let the ratio be k:1 in which given line 2x+y−4=0 divides the line segment joining the points
A(2,−2)andB(3,7) .
Then, by using the section formula we can find the coordinate of the point which divides the line segment joining the points A(2,−2)andB(3,7) .
Therefore, we have:
x=k+13k+2,y=k+17k−2
Since, this point is common on line segment joining points A(2,−2)andB(3,7) and line 2x+y−4=0 .
Therefore, substituting the value of ‘x’ and ‘y’ in the given equation and simplifying to get the value of k.
2(k+13k+2)+(k+17k−2)−4=0 ⇒k+16k+4+k+17k−2−4=0
takingLCM k+16k+4+7k−2−4(k+1)=0
⇒k+113k+2−4k−4=0 ⇒k+19k−2=0 ⇒9k−2=0 ⇒9k=2 ⇒k=92
Therefore, from above we can see that the value of k is 92 or we can say that ratio is 92 .
Hence, we see that line 2x+y−4=0 divides line segment joining points A(2,−2)andB(3,7) in ratio 92 .
So, the correct answer is “ 92”.
Note : For this type of problem we can either take the ratio as in terms of a:b and then use the section formula to find coordinates of the points which lie on both line segments joining given points and on a given line. Then substituting the coordinate of this point in the given line to form an equation in terms of a and b then finding the value of ba by dividing the whole equation by b and hence required ratio asked in the given problem.