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Question: Determine the number of photons emitted by the laser each second. (A) \(3.18 \times {10^{15}}\) ...

Determine the number of photons emitted by the laser each second.
(A) 3.18×10153.18 \times {10^{15}}
(B) 4.5×10164.5 \times {10^{16}}
(C) 1.2×10151.2 \times {10^{15}}
(D) 2.9×10172.9 \times {10^{17}}

Explanation

Solution

Photons always travel discreetly in packets. One photon has the energy hνh\nu . The energy is always in the integral multiple of hνh\nu . Find the ratio of the total energy to the energy of one photon to solve this question.

Formula Used: E=nhvE = nhv
where,
EE is energy
nn is number of photons
h=6.62×1034Jsh = 6.62 \times {10^{ - 34}}Js
n.vn.v should have units of photons second

Complete step by step answer:
We know energy of each photons is given by
E=hcλE = \dfrac{{hc}}{\lambda }
Let nn is the no. of photons. Total energy by n photons is
nE=nhcλ\Rightarrow nE = \dfrac{{nhc}}{\lambda }
We know that power is the energy required per unit time to perform some action. i.e.
P=ETP = \dfrac{E}{T}
Where,
PP is power
EE is energy
TT is time
By substituting the value of EE in the above formula, we get
P=nhcλtP = \dfrac{{nhc}}{{\lambda t}}
P=nt×hcλ\Rightarrow P = \dfrac{n}{t} \times \dfrac{{hc}}{\lambda }
Therefore, we can say that, power is equal to the product of number of photons emitted per second and energy of each photon
The energy of photons is

E=hcλ (6.62×1034)(5×108)632.8×109 3.14×109J \begin{aligned} E &= \dfrac{{hc}}{\lambda } \\\ \Rightarrow &\dfrac{{(6.62 \times {{10}^{ - 34}})(5 \times {{10}^8})}}{{632.8 \times {{10}^{ - 9}}}} \\\ \Rightarrow &3.14 \times {10^{ - 9}}J \\\ \end{aligned}

We know that, energy emitted per second by a laser, El{E_l} is 5mW5mW
El=5×103J\Rightarrow {E_l} = 5 \times {10^{ - 3}}J
Thus, the no. of photons emitted per second is
n=ElEn = \dfrac{{{E_l}}}{E}
By substituting the value of El{E_l} and EE, we get

n=ElE 5×1033.14×1019 1.6×1016 \begin{aligned} n &= \dfrac{{{E_l}}}{E} \\\ \Rightarrow &\dfrac{{5 \times {{10}^{ - 3}}}}{{3.14 \times {{10}^{ - 19}}}} \\\ \Rightarrow &1.6 \times {10^{16}} \\\ \end{aligned}

Additional information:
According to the equation E=n.h.vE = n.h.v (Energy == number of photons times Planck’s constant times the frequency)
You divide by Planck’s constant you should get photons per second
Eh=n.v\dfrac{E}{h} = n.v

Note: To solve this question, you have to keep in mind the law of quantization of energy which says that the energy is always produced in the integral multiple of energy of each photon. Energy of lasers is the total energy produced by all the photons that a laser emits.