Question
Question: Determine the number of photons emitted by the laser each second. (A) \(3.18 \times {10^{15}}\) ...
Determine the number of photons emitted by the laser each second.
(A) 3.18×1015
(B) 4.5×1016
(C) 1.2×1015
(D) 2.9×1017
Solution
Photons always travel discreetly in packets. One photon has the energy hν. The energy is always in the integral multiple of hν. Find the ratio of the total energy to the energy of one photon to solve this question.
Formula Used: E=nhv
where,
E is energy
n is number of photons
h=6.62×10−34Js
n.v should have units of photons second
Complete step by step answer:
We know energy of each photons is given by
E=λhc
Let n is the no. of photons. Total energy by n photons is
⇒nE=λnhc
We know that power is the energy required per unit time to perform some action. i.e.
P=TE
Where,
P is power
E is energy
T is time
By substituting the value of E in the above formula, we get
P=λtnhc
⇒P=tn×λhc
Therefore, we can say that, power is equal to the product of number of photons emitted per second and energy of each photon
The energy of photons is
We know that, energy emitted per second by a laser, El is 5mW
⇒El=5×10−3J
Thus, the no. of photons emitted per second is
n=EEl
By substituting the value of El and E, we get
Additional information:
According to the equation E=n.h.v (Energy = number of photons times Planck’s constant times the frequency)
You divide by Planck’s constant you should get photons per second
hE=n.v
Note: To solve this question, you have to keep in mind the law of quantization of energy which says that the energy is always produced in the integral multiple of energy of each photon. Energy of lasers is the total energy produced by all the photons that a laser emits.