Question

Determine the molecular mass of $ZnS{O_4}$
[Atomic mass of $Zn = 65u$ , $S = 32u$ , $O = 16u$ ]

Answer 1

We have to know that, an atomic number, the quantity of a substance component in the intermittent framework, whereby the components are orchestrated by expanding the number of protons in the core. Likewise, the quantity of protons, which is consistently equivalent to the quantity of electrons in the unbiased molecule, is additionally the nuclear number.

Complete answer:
We have to know that, the absolute amount of the majority of the iotas or components present in the particle is named as atomic mass.
We can track down the atomic mass of the particle by following the given substance:
Distinguish the recipe of the compound or particle.
Utilizing the recipe decides the quantity of iotas present in every component of the compound or particle.
Increase the nuclear load of every component with the quantity of iotas of that specific component.
Likewise, do it for every one of the components in the particle or compound.
Include every one of the qualities acquired in the above advance.
At that point add the unit as grams/mole you will get the sub-atomic mass of the substance.
In the given compound is $ZnS{O_4}$ ,
Atomic masses are$Zn = 65u$ , $S = 32u$ , $O = 16u$ ,
Now, adding the all the given atomic masses,
$[Atomic{\text{ mass of Zn + Atomic mass of S + 4}} \times {\text{Atomic mass of O]}}$
So that,
$65u + 32u + \left( {4 \times 16u} \right)$
Hence,
The value is $161u$ .
Therefore, the molecular mass of $ZnS{O_4}$ is$161u$ .

Note:
We have to know that, the molecular mass is a proportion that is utilized to change a mass estimation over to a measure of substance. This sum is communicated, as various particles, like atoms, or particles. It is the proportion between the mass of something, and the quantity of particles that structure it.