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Question: Determine the electrical potential energy for a system of three point charges....

Determine the electrical potential energy for a system of three point charges.

Explanation

Solution

Electrical potential energy, charge at a point is defined as the amount of work done, bringing the charge from infinity to that point. It is denoted by UU. The difference in potential energy between two points in an electric field is called electrical potential energy.

Complete step by step answer:
First we calculate the difference between two point charges, later we can discuss about three point charges. Electric potential energy of the system for two point charges. Suppose assume that two charges q1{q_1} and q2{q_2} are situated at a distance of rr.The electrical potential energy is:
U=14πe×q1q2rU = \dfrac{1}{{4\pi {e_ \circ }}} \times \dfrac{{{q_1}{q_2}}}{r}
When charge q1{q_1}is bought from infinity to certain position, no work is done. There is no other charge to repel each other. Now, the position of charge is q2{q_2}
V1=14πe×q1r{V_1} = \dfrac{1}{{4\pi {e_ \circ }}} \times \dfrac{{{q_1}}}{r} this equation is from electric field,
Therefore the work done bringing the charge q2{q_2} to infinity to its own position
W=U=V1q2W = U = {V_1}{q_2}
In the above equation we are substituting the V1{V_1} then we get,
U=14πe×q1q2r(1)U = \dfrac{1}{{4\pi {e_ \circ }}} \times \dfrac{{{q_1}{q_2}}}{r} \to \left( 1 \right)
Both the charges are in the same nature, the potential energy is positive for unlike charges it will be negative.

Electrical potential energy of a system of three charges: Consider three charges q1,q2,q3{q_1}, {q_2}, {q_3}, the charges q2{q_2} and q3{q_3} initially at finite distance from the charge q1{q_1} work done bringing charge q2{q_2} from infinity to point,
W12=14πe×q1q2r12(2){W_{12}} = \dfrac{1}{{4\pi {e_ \circ }}} \times \dfrac{{{q_1}{q_2}}}{{{r_{12}}}} \to \left( 2 \right)
Work done bringing charges q3{q_3} then we get,
W123=V1q3+V2q3 W123=14πe×q1q3r31+14πe×q2q3r23(3) {W_{123}} = {V_1}{q_3} + {V_2}{q_3} \\\ \Rightarrow {W_{123}} = \dfrac{1}{{4\pi {e_ \circ }}} \times \dfrac{{{q_1}{q_3}}}{{{r_{31}}}} + \dfrac{1}{{4\pi {e_ \circ }}} \times \dfrac{{{q_2}{q_3}}}{{{r_{23}}}} \to \left( 3 \right) \\\
Therefore the total work done is, work done by two point charges and work done by three point charges, here we get the total work done at some infinite point
W=W12+W123 W=14πe×q1q2r12+14πe×q1q3r31+14πe×q2q3r23 W=14πe[q1q2r12+q1q3r31+q2q3r23] W = {W_{12}} + {W_{123}} \\\ \Rightarrow W = \dfrac{1}{{4\pi {e_ \circ }}} \times \dfrac{{{q_1}{q_2}}}{{{r_{12}}}} + \dfrac{1}{{4\pi {e_ \circ }}} \times \dfrac{{{q_1}{q_3}}}{{{r_{31}}}} + \dfrac{1}{{4\pi {e_ \circ }}} \times \dfrac{{{q_2}{q_3}}}{{{r_{23}}}} \\\ \Rightarrow W = \dfrac{1}{{4\pi {e_ \circ }}}\left[ {\dfrac{{{q_1}{q_2}}}{{{r_{12}}}} + \dfrac{{{q_1}{q_3}}}{{{r_{31}}}} + \dfrac{{{q_2}{q_3}}}{{{r_{23}}}}} \right] \\\
Total work done in electrical potential energy is stored in the form of potential energy,
The electrical potential energy for a system of three point charges is,
U=12[14πeallpairsqiqjrij](4)\therefore U = \dfrac{1}{2}\left[ {\dfrac{1}{{4\pi {e_ \circ }}}\sum\limits_{allpairs} {\dfrac{{{q_i}{q_j}}}{{{r_{ij}}}}} } \right] \to \left( 4 \right)
In the above equation (4) we have multiplied 12\dfrac{1}{2} because each pair comes two times.

Note: The electric potential is charged at a point to bring charge from infinity point to certain point; according to the above data we have calculated the electrical potential charge for two points and for three points. Same method is used to calculate the electrical potential at three points.