Solveeit Logo

Question

Mathematics Question on Differential equations

Determine order and degree (if defined) of differential equation(d2ydx2)2ˆ+cos(dydx)=0\Big(\frac{d^2y}{dx^2}\Big)\\\^2+\cos\Big(\frac{dy}{dx}\Big)=0

Answer

(d2ydx2)2ˆ+cos(dydx)=0\Big(\frac{d^2y}{dx^2}\Big)\\\^2+\cos\Big(\frac{dy}{dx}\Big)=0
The highest order derivative present in the given differential equation is d2ydx2\frac{d^2y}{dx^2} .
Therefore, its order is 2.
The given differential equation is not a polynomial equation in its derivatives.

Hence, its degree is not defined.