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Question

Question: Derive the formula for equivalent capacitance when the capacitors are connected in series....

Derive the formula for equivalent capacitance when the capacitors are connected in series.

Explanation

Solution

Hint
Two conducting plates separated by a distance is called a capacitor. On the application of current, the plates will get charged with the opposite charge. In a series connection, the capacitors are connected in an end to end connection. In a series connection, each capacitor will carry the same amount of charge.

Complete step by step answer
Consider a series combination of capacitors, where the capacitors are connected in an end to end connection as shown in the figure.

Let VV be the potential difference applied across the series combination. The one property that we have to take care of in a series combination is that each capacitor will have the same amount of charge.
Let the potential difference be, V1,V2{V_1},{V_2} and V3{V_3} across the capacitors, C1,C2{C_1},{C_2} and C3{C_3} respectively,
\therefore We can write the applied potential as,
V=V1+V2+V3\Rightarrow V = {V_1} + {V_2} + {V_3}
The potential difference of each capacitor can be written as,
V1=Q1C1,V2=Q2C2\Rightarrow {V_1} = \dfrac{{{Q_1}}}{{{C_1}}},{V_2} = \dfrac{{{Q_2}}}{{{C_2}}} and V3=Q3C3{V_3} = \dfrac{{{Q_3}}}{{{C_3}}}
If we replace the combination of capacitors with a single capacitor, then we can write the effective resistance as,
V=QC\Rightarrow V = \dfrac{Q}{C}
Substituting equation and in equation we get,
QC=[Q1C1+Q2C2+Q3C3]\Rightarrow \dfrac{Q}{C} = \left[ {\dfrac{{{Q_1}}}{{{C_1}}} + \dfrac{{{Q_2}}}{{{C_2}}} + \dfrac{{{Q_3}}}{{{C_3}}}} \right]
From this we get the effective capacitance as,
1C=1C1+1C2+1C3\Rightarrow \dfrac{1}{C} = \dfrac{1}{{{C_1}}} + \dfrac{1}{{{C_2}}} + \dfrac{1}{{{C_3}}}
Thus we get that, the reciprocal of the effective capacitance is equal to the sum of the reciprocal of the individual capacitances.

Note
In a series combination, the effective capacitance will be less than the lowest capacitance in the combination. Thus a series combination is used to reduce the effective capacitance. The effective capacitance in a parallel combination is higher than the highest value of capacitance in the combination. Thus a parallel combination is used to increase the effective capacitance of the circuit.