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Question: Derivative of \[e^{2x}\] ?...

Derivative of e2xe^{2x} ?

Explanation

Solution

In this question , we need to find the derivative of e2xe^{2x} . Mathematically, a derivative is defined as a rate of change of function with respect to an independent variable given in the function. The term differentiation is nothing but it is a process of determining the derivative of a function at any point. With the help of the derivative chain rule, we can find the derivative of e2xe^{2x}.
Chain rule :
Chain rule is the derivative of the composite function which is the product of the derivative of the first function and derivative of the second function of the composite function. The use of chain rule is to find the derivative of the composite function.
dydx=dudx×dydu\dfrac{dy}{{dx}} = \dfrac{{du}}{{dx}} \times \dfrac{{dy}}{{du}}
Where, dydx \dfrac{{dy}}{{dx}}\ is the derivative of yy with respect to xx
dudx \dfrac{{du}}{{dx}}\ is the derivative of u with respect to xx
dydu\dfrac{{dy}}{{du}} is the derivative of yy with respect to uu
Derivative formulae used :
1. ddx(x)=1\dfrac{d}{{dx}}\left( x \right) = 1
2. ddx(ex)=ex\dfrac{d}{{dx}}\left( e^{x} \right) = e^{x}

Complete step by step solution:
Given, e2xe^{2x}
Let us consider y=e2x y = e^{2x}\
Here we will chain rule to find the derivative of e2xe^{2x} .
Chain rule :
dydx=dudx×dydu\dfrac{dy}{{dx}} = \dfrac{{du}}{{dx}} \times \dfrac{{dy}}{{du}}
y=e2x\Rightarrow y = e^{2x}
Let us consider 2x=u2x = u
u=2x\Rightarrow u = 2x
We get, y=euy = e^{u}
First we can differentiate uu,
u=2xu = 2x
Differentiating both sides with respect to xx ,
We get,
ddx(u)=ddx(2x)\Rightarrow\dfrac{d}{{dx}}\left( u \right) = \dfrac{d}{{dx}}\left( 2x \right)
By taking the constant outside,
ddx(u)=2ddx(x)\Rightarrow\dfrac{d}{{dx}}\left( u \right) = 2\dfrac{d}{{dx}}\left( x \right)
We know that ddx(x)=1\dfrac{d}{{dx}}\left( x \right) = 1
Thus we get, dudx=2\dfrac{{du}}{{dx}} = 2
Now we need to differentiate y=euy = e^{u}
Differentiating both sides with respect to uu,
ddu(y)=d(eu)du\Rightarrow\dfrac{d}{{du}}\left( y \right) = \dfrac{d\left( e^{u} \right)}{{du}}
We know that ddx(ex)=ex\dfrac{d}{{dx}}\left( e^{x} \right) = e^{x}
Thus we get, dydu=eu\dfrac{{dy}}{{du}} = e^{u}
By substituting the values in the chain rule formula,
dydx=dudx×dydu\Rightarrow\dfrac{dy}{{dx}} = \dfrac{{du}}{{dx}} \times \dfrac{{dy}}{{du}}
Here, dudx=2\dfrac{{du}}{{dx}} = 2 and dydu=eu\dfrac{{dy}}{{du}} = e^{u}
We get,
dydx=2×eu\Rightarrow\dfrac{{dy}}{{dx}} = 2 \times e^{u}
By substituting u=2xu = 2x ,
We get,
dydx=2e2x\dfrac{dy}{{dx}} = 2e^{2x}
Thus we get the derivative of e2xe^{2x} is 2e2x2e^{2x}
The derivative of e2xe^{2x} is 2e2x2e^{2x}

Note: Mathematically, derivative helps in solving the problems in calculus and in differential equations. The derivative of yy with respect to xx is represented as dydx\dfrac{{dy}}{{dx}}. Here the notation dydx\dfrac{{dy}}{{dx}} is known as Leibniz's notation . In derivation, there are two types of derivative namely first order derivative and second order derivative. A simple example for a derivative is the derivative of x3x^{3} is 3x3x . Derivative is applicable in trigonometric functions also.