Question
Chemistry Question on Thermodynamics
ΔH for the reaction, OF2+H2O→O2+2HF (B.E. of $O ?
A
−222kcal
B
−88kcal
C
−111kcal
D
−79kcal
Answer
−79kcal
Explanation
Solution
ΔH=ΣB.E.R−ΣB.E.P =(2×44+2×111)−(119+2×135) =−79kcal
ΔH for the reaction, OF2+H2O→O2+2HF (B.E. of $O ?
−222kcal
−88kcal
−111kcal
−79kcal
−79kcal
ΔH=ΣB.E.R−ΣB.E.P =(2×44+2×111)−(119+2×135) =−79kcal