Solveeit Logo

Question

Chemistry Question on Thermodynamics

ΔH\Delta H for the reaction, OF2+H2OO2+2HFOF_2 + H_2O \to O_2 + 2HF (B.E.(B.E. of $O ?

A

222kcal- 222\, kcal

B

88kcal- 88\, kcal

C

111kcal- 111\, kcal

D

79kcal- 79\, kcal

Answer

79kcal- 79\, kcal

Explanation

Solution

ΔH=ΣB.E.RΣB.E.P\Delta H = \Sigma\,B.E._{R} - \Sigma\,B.E._{P} =(2×44+2×111)(119+2×135)= \left(2 \times 44 + 2 \times 111\right) - \left(119 + 2 \times 135\right) =79kcal = - 79 \,kcal