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Question: \(\Delta G^{0}\) for the reaction \(x + y = z\) is – 4.606 kcal. The value of equilibrium constant o...

ΔG0\Delta G^{0} for the reaction x+y=zx + y = z is – 4.606 kcal. The value of equilibrium constant of the reaction at 227oC227^{o}C is (R=2.0kcalmol−1K−1)(R = 2.0kcalmol^{- 1}K^{- 1})

A

100

B

10

C

2

D

0.01

Answer

100

Explanation

Solution

R=2.0kcalmol−1K−1R = 2.0kcalmol^{- 1}K^{- 1}; T = 500 K ; ΔG0=−4.606kcal\Delta G^{0} = - 4.606kcal;

ΔG0=−2.303RTlog⁡K\Delta G^{0} = - 2.303RT\log K

−4.606=−2.303×0.002×500log⁡K\mathbf{-}\mathbf{4.606 =}\mathbf{-}\mathbf{2.303}\mathbf{\times}\mathbf{0.002}\mathbf{\times}\mathbf{500}\mathbf{\log}\mathbf{K}

log⁡K=2,K=100\mathbf{\log}\mathbf{K}\mathbf{= 2,K = 100}