Question: $\Delta Gº$ for the reaction $Cu^{2 +} + Fe \rightarrow Fe^{2 +} + Cu$ is (Given: \(Eº_{cu^{2 +...

Question

$\Delta Gº$ for the reaction $Cu^{2 +} + Fe \rightarrow Fe^{2 +} + Cu$ is

(Given: $Eº_{cu^{2 +}|Cu} = + 0.34V,Eº_{Fe^{2 +}|Fe} = - 0.44V$ )

Answer 1

$Eº_{cell} = Eº_{Cu^{2 +}/Cu} - Eº_{Fe^{2 +}/Fe}$

$= 0.34V - ( - 0.44)V = 0.78V$

$\Delta Gº = - nFEº_{cell}$

$= - 2 \times 96500 \times 0.78 = 150540Jor150.5kJ$

Question: \(\Delta Gº\) for the reaction \(Cu^{2 +} + Fe \rightarrow Fe^{2 +} + Cu\) is (Given: \(Eº_{cu^{2 +...