(\Delta G ^ \circ ,Vs, T) plot in the Ellingham's diagram sl... | Chemistry | SolveeIt

Question

$\Delta G ^ \circ \,Vs\, T$ plot in the Ellingham's diagram slopes downwards for the reaction

$Mg + \frac {1}{2}O_2 \rightarrow MgO$

$2Ag + \frac {1}{2}O_2 \rightarrow Ag_2O$

$C + \frac {1}{2} O_2 \rightarrow CO$

$CO +\frac{1}{2} O_2 \rightarrow CO_2$

Answer

$C + \frac {1}{2} O_2 \rightarrow CO$

Explanation

Solution

In Ellingham diagram, higher is the slope higher is the entropy change so $\Delta S \left( C _{( s )}+1 / 2 O _{2( g )} \longrightarrow CO _{( g )}\right)>\Delta S \left( C _{( S )}+ O _{2( g )} \longrightarrow CO _{2( g )}\right.$
as CO have higher slope.

Also, Carbon monoxide is a more effective reducing agent than carbon below $983 K$ but above this temperature the reverse is true.

Chemistry Question on General Principles and Processes of Isolation of Elements

Solution