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Question: \(\Delta G ^ { 0 }\) for \(H I _ { ( g ) } \cong + 1.7 \mathrm {~kJ} / \mathrm { mole }\) what is...

ΔG0\Delta G ^ { 0 } for HI(g)≅+1.7 kJ/moleH I _ { ( g ) } \cong + 1.7 \mathrm {~kJ} / \mathrm { mole } what is the equilibrium constant at 25∘C25 ^ { \circ } \mathrm { C } for 2HI(g)2 H I _ { ( g ) } ⇌H2(g)+I2(g)H _ { 2 ( g ) } + I _ { 2 ( g ) }

A

24.0

B

3.9

C

2.0

D

0.5

Answer

0.5

Explanation

Solution

ΔG0=−2.303RTlog⁡Kp=−2.303×8.314×10−3×298log⁡Kp\Delta G ^ { 0 } = - 2.303 R T \log K _ { p } = - 2.303 \times 8.314 \times 10 ^ { - 3 } \times 298 \log K _ { p }

1.7=−2.303×8.314×10−3×298log⁡Kp1.7 = - 2.303 \times 8.314 \times 10 ^ { - 3 } \times 298 \log K _ { p }

Kp=0.5K _ { p } = 0.5