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Question

Chemistry Question on Ionic Equilibrium In Solution

Degree of dissociation of NH4OHNH _{4} OH in water is 1.8×10−51.8 \times 10^{-5}, then hydrolysis constant of NH4ClNH _{4} Cl is :

A

1.8×10−5 1.8\times 10^{-5}

B

1.8×10−10 1.8\times 10^{-10}

C

5.55×10−5 5.55\times 10^{-5}

D

5.55×10−10 5.55\times 10^{-10}

Answer

5.55×10−10 5.55\times 10^{-10}

Explanation

Solution

We know KH=KwKbK_{H}=\frac{K_{w}}{K_{b}} Here KH=?K_{H}=? Kw=10−14,K_{w} =10^{-14}, Kb=1.8×10−5K_{b}=1.8 \times 10^{-5} KH=10−141.8×10−5K_{H} =\frac{10^{-14}}{1.8 \times 10^{-5}} =0.555×10−9=0.555 \times 10^{-9} =5.55×10−10=5.55 \times 10^{-10}