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Question: Define the following and write the formula and unit of each: (A) Specific Conductivity. (B) Mol...

Define the following and write the formula and unit of each:
(A) Specific Conductivity.
(B) Molar Conductivity.

Explanation

Solution

Hint : We know that equivalent conductance is defined as the conductance of all the ions produced by one-gram equivalent of an electrolyte in a given solution. In case, if the concentration of the solution is c gram equivalent per litre, then the volume containing 11 g equivalent of the electrolyte will be 1000/e.1000/e.

Complete Step By Step Answer:
Specific Conductivity: It decreases with a decrease in concentration. As the number of ions per unit volume that carry current in a solution decreases on dilution. Thus, concentration and conductivity are directly proportional to each other. Specific Conductance is the conductance of a given solution enclosed in a cell having two electrodes which are of unit area and are separated by 1cm.1cm.
Formula - κ=1ρ=1A×lR\kappa = \dfrac{1}{\rho} = \dfrac{1}{A} \times \dfrac{l}{R}
Where, ρ=  specific  resistance\rho = \;specific\;resistance
l=  lengthl = \;length
A=  AreaA = \;Area
R=  ResistanceR= \;Resistance
Unit - Ohm1  cm1Ohm^{-1}\;cm^{-1}

Molar conductivity: It is the conductance property of a solution containing one mole of the electrolyte or it is a function of the ionic strength of a solution or the concentration of salt. It is therefore not a constant. In other words, molar conductivity can also be defined as the conducting power of all the ions that are formed by dissolving a mole of electrolyte in a solution. Molar conductivity is the property of an electrolyte solution that is mainly used in determining the efficiency of a given electrolyte in conducting electricity in a solution. It is therefore not a constant.
Formula - μ=κ×V\mu = \kappa \times V
μ=κ×1000m\mu = \kappa \times \dfrac{1000}{m}
Where, μ=  molar  conductivity\mu = \;molar\;conductivity
κ=  specific  conductivity\kappa = \;specific\;conductivity
m=  molaritym = \;molarity
V=  volumeV= \;volume
Unit - Ohm1  cm2  mol1Ohm^{-1}\;cm^{2}\;mol^{-1}

Note :
Remember that we should also know the effect of concentration on molar conductivity. The molar conductivity of both weak and strong electrolytes increases with a decrease in concentration or dilution. We know that the molar conductivity is the conductivity offered by one mole of ions.