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Question: Define impulse. State its S.I. unit. State and prove impulse-momentum theorem. A batsman deflects a ...

Define impulse. State its S.I. unit. State and prove impulse-momentum theorem. A batsman deflects a ball by an angle of 4545^{\circ} without changing its initial speed which is equal to 54Kmhr154 Km hr^{-1}. What is the impulse imparted to the ball (Mass of the ball is 0.150.15kg)?

Explanation

Solution

Impulse can be described as the change in momentum of an object to which force is implemented. An object in the behaviour of any force accelerates or changes the velocity. The same force appearing on the same body for a long time will produce a more significant change in its linear momentum than the equivalent for a short duration.

Complete step by step answer:
Impulse defined as a force applied on an object for a short duration of time. Its S.I. unit is Ns. It is defined as the 11 N force applied on a body for one second of time.
Impulse-momentum theorem states that Impulse applying on a body changes the same amount of linear momentum and change will occur in the same direction.
Proof: -
Let J is the impulse that produced between time t1t_{1} and t2t_{2}.
F is the force acting in the time interval of t1t_{1} and t2t_{2}.
We can write as –
J=t1t2FdtJ =\int_{t_{1}}^{t_{2}} F dt
By Newton’s second law, Force and momentum can related as-
F=dpdtF = \dfrac{dp}{dt}
    J=t1t2dpdtdt\implies J =\int_{t_{1}}^{t_{2}} \dfrac{dp}{dt} dt
    J=p1p2dp\implies J =\int_{p_{1}}^{p_{2}} dp
    J=p2p1\implies J=p_{2}-p_{1}
Hence proved, impulse is equal to the change in linear momentum.
Given: - initial speed, u =54Kmhr1=54×518=15ms154 Km hr^{-1} = 54 \times \dfrac{5}{18} =15 m s^{-1}
Initial speed is equal to final speed.
Mass of the ball = 0.15Kg0.15 Kg
Ball is deviated at 4545^{\circ} but the angle with the x-axis will be 22.522.5^{\circ}.

Initial momentum of ball = mucosθmucos \theta along PR
Final momentum of ball = mucosθmucos\theta along RP
 Impulse=Change in momentum\text{ Impulse} = \text{Change in momentum}
J=2mucosθJ=2mucos\theta
    J=2×0.15×15×cosθ\implies J= 2\times 0.15\times 15\times cos\theta
    J=4.16Kgms1\implies J=4.16 Kg m s^{-1}
\therefore Impulse imparted to the ball = 4.16Kgms14.16 Kg m s^{-1}

Note: A small force acted for a long span will produce the same change in momentum as an Impulse force for a small duration. Forces which are acted over a short time interval are called impulsive forces. Impulse is a vector quantity. It arises basically during the collision.