Question
Real Analysis Question on Sequences and Series
Define f: ℝ → ℝ and g: ℝ → ℝ as follows
f(x)=m=0∑∞22m(m!)2(−1)mx2m and g(x)=2xm=0∑∞22m(m+1)!m!(−1)mx2m for x ∈ R.
Let x1, x2, x3, x4 ∈ ℝ be such that 0 < x1 < x2 , 0 < x3 < x4,
f(x1) = f(x2) = 0, f(x) ≠ 0 when x1 < x < x2,
g(x3) = g(x4) = 0 and g(x) ≠ 0 when x3 < x < x4.
Then, which of the following statements is/are TRUE ?
The function f does not vanish anywhere in the interval (x3, x4)
The function f vanishes exactly once in the interval (x3, x4)
The function g does not vanish anywhere in the interval (x1, x2)
The function g vanishes exactly once in the interval (x1, x2)
The function f vanishes exactly once in the interval (x3, x4)
Solution
The correct option is (B) : The function f vanishes exactly once in the interval (x3, x4) and (D) : The function g vanishes exactly once in the interval (x1, x2).