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Question

Real Analysis Question on Sequences and Series

Define f: ℝ → ℝ and g: ℝ → ℝ as follows
f(x)=m=0(1)mx2m22m(m!)2f(x)=\sum\limits^{\infin}_{m=0}\frac{(-1)^mx^{2m}}{2^{2m}(m!)^2} and g(x)=x2m=0(1)mx2m22m(m+1)!m!g(x)=\frac{x}{2}\sum\limits^{\infin}_{m=0}\frac{(-1)^mx^{2m}}{2^{2m}(m+1)!m!} for x ∈ R\R.
Let x1, x2, x3, x4 ∈ ℝ be such that 0 < x1 < x2 , 0 < x3 < x4,
f(x1) = f(x2) = 0, f(x) ≠ 0 when x1 < x < x2,
g(x3) = g(x4) = 0 and g(x) ≠ 0 when x3 < x < x4.
Then, which of the following statements is/are TRUE ?

A

The function f does not vanish anywhere in the interval (x3, x4)

B

The function f vanishes exactly once in the interval (x3, x4)

C

The function g does not vanish anywhere in the interval (x1, x2)

D

The function g vanishes exactly once in the interval (x1, x2)

Answer

The function f vanishes exactly once in the interval (x3, x4)

Explanation

Solution

The correct option is (B) : The function f vanishes exactly once in the interval (x3, x4) and (D) : The function g vanishes exactly once in the interval (x1, x2).