Question

Decreasing order of stability of given carbocations is as :

(1) $\stackrel { \oplus } { \mathrm { C } } \mathrm { H } _ { 2 }$

(3) C₆H₅–$\stackrel { \oplus } { \mathrm { C } } \mathrm { H } _ { 2 }$ (4) CH₃––CH₃

• A. 3 > 2 > 4 > 1
• B. 1 > 3 > 4 > 2
• C. 1 > 3 > 2 > 4
• D. 3 > 2 > 1 > 4

Answer 1

Answer: (C)

1 > 3 > 2 > 4

Answer 2

(1) $\stackrel { \oplus } { \mathrm { C } } \mathrm { H } _ { 2 }$

Aromatic R.S. = 2

(3) C₆H₅–$\stackrel { \oplus } { \mathrm { C } } \mathrm { H } _ { 2 }$ (4) CH₃––CH₃

R.S. = 4