Decreasing order of size of various hybrid orbitals is – | CHEMISTRY - HYBRIDISATION | SolveeIt

Decreasing order of size of various hybrid orbitals is –

$sp > sp^{2} > sp^{3}$

$sp^{3} > sp^{2} > sp$

$sp^{2} > sp > sp^{3}$

$sp > sp^{3} > sp^{2}$

Answer

$sp > sp^{3} > sp^{2}$

Explanation

Here $\overset{1}{C},\overset{2}{C},\overset{5}{C},\&\overset{6}{C}$ are sp² hybridised

So total no. of carbon atoms having sp² configuration is 4

Question: Decreasing order of size of various hybrid orbitals is –...