Question
Question: de-Broglie wavelength of electron in second orbit of Li2+ ion will be equal to de-Broglie of wavelen...
de-Broglie wavelength of electron in second orbit of Li2+ ion will be equal to de-Broglie of wavelength of electron in
A
n = 3 of H-atom
B
n = 4 of C5+ ion
C
n = 6 of Be3+ ion
D
n = 3 of He+ ion
Answer
n = 4 of C5+ ion
Explanation
Solution
}{\frac{2}{3} = \frac{4}{6}\left( n = \frac{2}{3} = \frac{4}{6} \right)\left( n = 4ofC^{5 +}ion \right)}$$