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Question: De Broglie wavelength \(\lambda \) associated with neutrons is related with absolute temperature \(T...

De Broglie wavelength λ\lambda associated with neutrons is related with absolute temperature TT as:
(A) λT\lambda \propto T
(B) λ1T\lambda \propto \dfrac{1}{T}
(C) λ1T\lambda \propto \dfrac{1}{{\sqrt T }}
(D) λT2\lambda \propto {T^2}

Explanation

Solution

Hint De Broglie proposed that matter is associated with a wave called matter-wave. According to him matter and energy could have symmetrical characteristics. The radiant energy has dual characteristics. Hence the matter should exhibit dual characteristics. We can find the temperature using the expression for the De Broglie wavelength of a particle.

Formula used:
λ=hmv\lambda = \dfrac{h}{{mv}}
Where, λ\lambda stands for the De Broglie wavelength of the particle, hh is the Planck’s constant, mm stands for the mass of the particle, vv stands for the velocity of the particle.

Complete step by step answer:
Consider a particle having a mass, mm moving with a velocity vv.
The De Broglie wavelength of the matter wave of the particle is given by,
λ=hp=hmv\lambda = \dfrac{h}{p} = \dfrac{h}{{mv}}
Where pp is the momentum of the particle.
The kinetic energy of the particle can be written as
E=12mv2E = \dfrac{1}{2}m{v^2}
From this equation we get
v2=2Em{v^2} = \dfrac{{2E}}{m}
v=2Em\Rightarrow v = \sqrt {\dfrac{{2E}}{m}}
Substituting this value of vvin the expression for wavelength, we get
λ=hm2Em=h2mE\lambda = \dfrac{h}{{m\sqrt {\dfrac{{2E}}{m}} }} = \dfrac{h}{{\sqrt {2mE} }}
We know that the energy of neutrons is directly proportional to the temperature, i.e. ETE \propto T
Since, λ1E\lambda \propto \dfrac{1}{{\sqrt E }} and ETE \propto T
We can write that
λ1T\lambda \propto \dfrac{1}{{\sqrt T }}

The answer is Option (C): λ1T\lambda \propto \dfrac{1}{{\sqrt T }}

Note
All the particles in quantum mechanics are manifested with De Broglie wavelength. The De Broglie wavelength gives the probability of finding a particle in a given configuration space. The equation for the De Broglie wavelength gives the wavelength of matter-wave. The wavelength is appreciable when the mass is very small and the velocity is very large. The matter-wave associated with moving electrons can be verified by crystal diffraction experiments (Davisson and Germer experiment). De Broglie was awarded the Nobel Prize for his discovery of the wave nature of electrons in 1929.