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Question

Question: \(\ddot{A} = \left| \begin{matrix} my + nz & mq - nr & mb + nc \\ kz - mx & kr - mp & kb - ma \\ nx ...

A¨=my+nzmqnrmb+nckzmxkrmpkbmanx+kynp+kqna+kb\ddot{A} = \left| \begin{matrix} my + nz & mq - nr & mb + nc \\ kz - mx & kr - mp & kb - ma \\ nx + ky & np + kq & na + kb \end{matrix} \right|is equal to

A

∆ = 0

B

∆≠ 0

C

∆ = f(x,y,z)

D

None

Answer

∆ = 0

Explanation

Solution

∆ = $\left| \begin{matrix} x & y & z \ p & q & r \ a & b & c \end{matrix} \right|\left| \begin{matrix} 0 & m & n \

  • m & 0 & k \
  • n & - k & 0 \end{matrix} \right| = 0$.