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Question: Dan either walks or cycles to school. The probability that he cycles to school is \(\dfrac{1}{3}\) ...

Dan either walks or cycles to school. The probability that he cycles to school is 13\dfrac{1}{3}
A.Write down the probability that Dan walks to school.
B.There are 198days in a school year. Work out the expected number of days that Dan cycles to school in a school year.

Explanation

Solution

The question is related to probability. We will use the formula of probability that is probability of event to happenP(E)=number of favourable outcomestotal number of outcome{\text{probability of event to happen}}P(E) = \dfrac{\text{number of favourable outcomes}}{\text{total number of outcome}}. The total probability of any event is always 1.

Complete step-by-step answer:
We have two condition in the question that is
Dan either walks or cycles to school and the probability that Dan cycles to school is 13\dfrac{1}{3}
We know that the total probability of any event is = 1
So, the probability that Dan walks to school is = total probability – probability that Dan cycles to school
= 1131 - \dfrac{1}{3}
Do the L.C.M
=313= \dfrac{{3 - 1}}{3}
Solve the above equation
=23= \dfrac{2}{3}
Hence the probability of Dan walks to school is 23\dfrac{2}{3}
(ii) Expected number of days that Dan cycles to school
expected number of days that Dan cycles to school in a school year=total number of days×probability that Dan cycles to school{\text{expected number of days that Dan cycles to school in a school year}} = {\text{total number of days}} \times {\text{probability that Dan cycles to school}}
=198×13= 198 \times \dfrac{1}{3}
Multiply and divide the above equation we get
=1983= \dfrac{198}{3}
=66= 66
Expected number of days is 66 days.

Note: If P is the probability of an event to occur then then the probability of that event to not occur is 1-P. The sum of probabilities of a particular event to occur and not occur is always equal to 1.