(d\pi - p \pi) bond present in : | Chemistry | SolveeIt

Question

$d\pi - p \pi$ bond present in :

$NO_2^-$

$NO_3^-$

$PO_4^{3-}$

$CO_3^{2-}$

Answer

$PO_4^{3-}$

Explanation

Solution

In P-O bond, $\pi$ -bond is formed by the sidewise overlapping of d-orbital of P and p-orbital of oxygen.
Hence, it is formed by $p\pi$ and $d \pi$ -overlapping.
In nitrogen and carbon, no vacant d-orbital is present. So, they do not form $p\pi - d \pi$ bond.

Chemistry Question on Chemical bonding and molecular structure

Solution