Question

D (+) glucose reacts with hydroxylamine and yields an oxime. The structure of the oxime would be:

Answer 1

The structure of D glucose and L glucose differs from each other in the position of the hydroxyl group that is on 4 and 5 carbon atoms. The product formed by the D glucose that is oxime will also have the D configuration.

Complete step by step answer:
- In the given question, we have to find the correct structure of oxime which will be formed by the reaction between D glucose and hydroxylamine.
- As we know that the D glucose has the hydroxyl group present at the right side on the 4 and 5 carbon whereas in L Glucose the hydroxyl group will be present at the left side.

- The structure of D glucose is:

- Now, when D glucose reacts with the hydroxylamine it will yield oxime. The product formed will also have the D configuration.
- As we can see the below-given reaction:

D (+) Glucose D - Oxime
- Here, we can see that hydroxylamine attacks only on the oxygen of the first carbon of the glucose molecules.
- There is no replacement of other hydroxyl and hydrogen groups from the glucose molecule that's why oxime also has the D configuration.
So, the correct answer is “Option D”.

Note: In L glucose, the hydroxyl that is present at 4 and 5 carbon will be at the left side. ${{\text{C}}_{6}}{{\text{H}}_{12}}{{\text{O}}_{6}}$ is the molecular formula of glucose. The molecular formula and weight of the D and L glucose remains the same only the arrangement of atoms is different.