Question

D-glucose, on treating with methanol in presence of dry HCl gives methyl glucosides according to the following reaction

$\xrightarrow [ \text { dry } \mathrm { HCl } ] { \mathrm { CH } _ { 3 } \mathrm { OH } }$

(I) (II) (III)

Mention true (T) and False (F) from the following statements

**S1 :**The glucosides do not reduce fehling's solution

**S2 :**The glucosides do not react with hydrogen cyanide or Hydroxylamine

**S3 :**Behaviour of glucosides as stated in S1 and S2 indicates the absence of free – CHO group.

**S4 :**The two forms of glucosides are enantiomers.

• A. TTFF
• B. FTTT
• C. TTTF
• D. TFTF

Answer 1

Answer: (C)

TTTF

Answer 2

S1, S2 and S3 are true but S4 is False because the glycosides are non-super impossible non-mirror images hence they are diastereomers.