Question

Cycle tyres are supplied in lots of 10 and there is a chance of 1 in 500 tyres to be defective. Then the approx. no. of lots containing no defective tyre in a consignment of 10,000 lots (given e^-0.02 = 0.9802) is

• A. 9802
• B. 4901
• C. 9801
• D. 4900

Answer 1

Answer: (A)

9802

Answer 2

For 1 lot, n = 10, P = $\frac { 1 } { 500 }$

λ = np = $\frac { 1 } { 50 } = 0.02$

Probability that a lot contains no defective

P = (X=0) =

Approx. no. of lots containing no defective = 0.9802 x 10,000 = 9802