Question

$CuSO_{4}$ is paramagnetic while $ZnSO_{4}$is diamagnetic because

• A. $Cu^{2 +}$ion has $3d^{9}$ configuration while $Zn^{2 +}$ion has $3d^{10}$configuration.
• B. $Cu^{2 +}$ion has $3d^{5}$ configuration while $Zn^{2 +}$ion has $3d^{6}$configuration
• C. $Cu^{2 +}$ has half filled orbitals while $Zn^{2 +}$ has fully filled orbitals
• D. $CuSO_{4}$is blue in colour while $ZnSO_{4}$is white.

Answer 1

Answer: (A)

$Cu^{2 +}$ion has $3d^{9}$ configuration while $Zn^{2 +}$ion has $3d^{10}$configuration.

Answer 2

$Cu^{2 +}$ has $3d^{9}$ configuration i.e, one unpaired electron while $Zn^{2 +}$ has $3d^{10}$ configuration i.e., all orbitals are filled hence it is diamagnetic in nature.