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Question

Chemistry Question on coordination compounds

CuSO4CuSO _{4} dissolves in NH3NH _{3} due to the formation of

A

Cu(OH)2Cu ( OH )_{2}

B

Cu[(NH3)4]SO4Cu \left[\left( NH _{3}\right)_{4}\right] SO _{4}

C

Cu[(NH3)4(OH)2]Cu \left[\left( NH _{3}\right)_{4}( OH )_{2}\right]

D

CuOCuO

Answer

Cu[(NH3)4]SO4Cu \left[\left( NH _{3}\right)_{4}\right] SO _{4}

Explanation

Solution

NH3+H2O−>NH4OH {NH3 + H2O -> NH4OH} CuSO4+2NH4OH−>Cu(OH)2+(NH4)2SO4 {CuSO4 + 2NH4OH -> Cu(OH)2 + (NH4 )2 SO4} Cu(OH)2+2NH4OH+(NH4)2SO4−>[Cu(NH3)4]SO4+4H2O {Cu(OH)2 + 2NH4 OH + (NH4)2SO4 -> [Cu(NH3)4] SO4 + 4H 2O} Tetraamminecupric sulphate