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Question: Curves ax<sup>2</sup> + by<sup>2</sup> = 1 & a'x<sup>2</sup> + b'y<sup>2</sup> = 1 intersects orthog...

Curves ax2 + by2 = 1 & a'x2 + b'y2 = 1 intersects orthogonally if –

A

1a–1b=1a′–1b′\frac{1}{a}–\frac{1}{b} = \frac{1}{a'}–\frac{1}{b'}

B

1a+1b=1a′+1b′\frac{1}{a} + \frac{1}{b} = \frac{1}{a'} + \frac{1}{b'}

C

1a+1a′=1b+1b′\frac{1}{a} + \frac{1}{a'} = \frac{1}{b} + \frac{1}{b'}

D

None of these

Answer

1a–1b=1a′–1b′\frac{1}{a}–\frac{1}{b} = \frac{1}{a'}–\frac{1}{b'}

Explanation

Solution

cond. ® 1a′–1a=1b′+1b\frac{1}{a'}–\frac{1}{a} = \frac{1}{b'} + \frac{1}{b} Ž 1a′–1b′=1a–1b\frac{1}{a'}–\frac{1}{b'} = \frac{1}{a}–\frac{1}{b}