Solveeit Logo
Login

Question

Physics Question on Current electricity

Currents of 10 A and 2 A are passed through two parallel wires A and B respectively in opposite directions. If the wire A is infinitely long and length of the wire B is 2 m, the force acting on the conductor B which is situated at 10 cm distance from A will be

A

5×10−5N5 \times 10^{-5}N

B

4π×10−7N4 \pi \times 10^{-7}N

C

8×10−5N8 \times 10^{-5}N

D

8π×10−7N8\pi \times 10^{-7}N

Answer

8×10−5N8 \times 10^{-5}N

Explanation

Solution

Force on a conductor of length l, carrying current I2I_2 and placed at a distance r parallel to another infinitely long conductor carrying current I1 isI_1 \, is \hspace5mm F=\frac {\mu _0}{4 \pi }. \frac {2I_1I_2}{r}l Here \hspace5mm I_1=10 \, A, I_2=2 \, A,l=2 \, m, \hspace5mm r=10cm=0.1m \therefore \hspace5mm F=10^{-7}\times \frac {2 \times 10 \times 2 \times 2}{0.1} \hspace5mm =8 \times 10^{-5}N