Question

Current gain for an npn CE configuration transistor is when the reading are shown in the graph –

• A. 2
• B. 2 × 10^–3
• C. 0.5
• D. 500

Answer 1

Answer: (D)

500

Answer 2

b = $\frac { \Delta \mathrm { I } _ { \mathrm { C } } } { \Delta \mathrm { I } _ { \mathrm { b } } }$ = $\frac { ( 2 - 1 ) \times 10 ^ { - 3 } } { ( 4 - 2 ) \times 10 ^ { - 6 } }$ = $\frac { 1 } { 2 }$× 1000 = 500