Question

$Cu$ crystallizes as face centred cubic lattice with edge length of $3.56 \, ?$ . What will be the nearest distance between $Cu$ atoms?

• A. $1.5 ?$
• B. $2.5 ?$
• C. $3.7 ?$
• D. $4.8 ?$

Answer 1

Answer: (B)

$2.5 ?$

Answer 2

For a face-centred cubic lattice, distance between nearest neighbour is given b y:
$d=\frac{a}{\sqrt{2}}$
$=\frac{3.56}{\sqrt{2}}$
$=2.51\, ?$