Question

C_eq between A and B –

• A. (a) $\frac{\in_{0}b}{d}$ [l + x (K – 1)]
• A. (b) Zero
• A. (c) Infinite
• A. (d) $\frac{\in_{0}b}{d}$ K x l

Answer 1

(a)

C_eq = C₁ + C₂

Now C₁ = K

C₂ =

C_eq = (Kx + l – x)

= [l + x (K – 1)]