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Chemistry Question on Redox reactions

Cr2O72−−>[H+]Cr3+, {Cr_2 O^{2-}_7 ->[H^+] Cr^{3+} , } E wt of Cr2O72− {Cr_2 O^{2-}_7} is

A

mol. wt./6

B

mol. wt/3

C

mol. wt./4

D

mol. wt/1

Answer

mol. wt./6

Explanation

Solution

Cr2O72−+14H++6e−−>2 Cr3++7H2O {Cr_2O^{2-}_7 + 14H^{+} + 6e^{-} -> 2 \, Cr^{3+} + 7 H_2O} It is a 6 e−e^{-} change, therefore, e wt. of Cr2O72−=Mol.wt.6 {Cr_2 O^{2-}_7 = \frac{Mol. wt.}{6}}