Question
Question: Could someone please help me prove this identity? \(\dfrac{1}{{\sec A - 1}} + \dfrac{1}{{\sec A + 1}...
Could someone please help me prove this identity? secA−11+secA+11=2cotAcosecA
Solution
In this question we need to use some identities of trigonometry to solve this question. The identities we need in this question are 1+tan2x=sec2x , secA=cosA1, cotA=sinAcosAand cosecA=sinA1. They need to be used in this question wherever we find their use while solving the question.
Complete step by step answer:
In the above question, let’s take L.H.S
⇒secA+11+secA−11
Now let’s take LCM and solve this question further.
⇒(secA+1)(secA−1)secA−1+secA+1
Using identity a2−b2=(a+b)(a−b) and on further simplification, we get
⇒(sec2A−1)2secA
Now using the identity 1+tan2x=sec2x and on further simplification, we get
⇒tan2A2secA
Now, we will use the identity tanA=cosAsinA.
⇒cos2Asin2A2secA
Now we will use the identity which will convert secA into cosAas secA=cosA1 and taking the cos2A to numerator.
⇒cosA2sin2Acos2A
Now cancelling the cosA
⇒2.sinAcosA.sinA1
Now we will use the identities cotA=sinAcosA and cosecA=sinA1.
⇒2cotAcosecA
Also, we have RHS=2cotAcosecA
Therefore, LHS=RHS
Hence proved.
Additional information: Trigonometric Identities are useful whenever trigonometric functions are involved in an expression or an equation. Identity inequalities which are true for every value occurring on both sides of an equation. Geometrically, these identities involve certain functions of one or more angles. There are various distinct identities involving the side length as well as the angle of a triangle. The trigonometric identities hold true only for the right-angle triangle.
Note: In this question we have used a lot of identities. Therefore, we need to remember all the identities as trigonometry is nothing without identities. Most of the questions we can just do by simply applying identities.