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Question

Mathematics Question on Inverse Trigonometric Functions

cot⁡−1(2+3)=\cot^{-1} (2 + \sqrt{3}) =

A

π12\frac{\pi}{12}

B

π15\frac{\pi}{15}

C

π5\frac{\pi}{5}

D

3π10\frac{3\pi}{10}

Answer

π12\frac{\pi}{12}

Explanation

Solution

2+3=cot⁡15∘ 2 + \sqrt{3} = \cot 15^{\circ}