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Question

Mathematics Question on Inverse Trigonometric Functions

cos⁡(sin⁡−1513)=\cos\left(\sin^{-1} \frac{5}{13}\right) =

A

44908

B

44693

C

44694

D

13/5

Answer

44908

Explanation

Solution

sin⁡−1513=cos⁡−11213\sin^{-1} \frac{5}{13} = \cos^{-1} \frac{12}{13}