QuestionReportQuestion: \[{\cos h}2 + {\sin h}2 =\]...cosh2+sinh2={\cos h}2 + {\sin h}2 =cosh2+sinh2=A1e\frac{1}{e}e1BeeeC1e2\frac{1}{e^{2}}e21De2e^{2}e2Answere2e^{2}e2ExplanationSolutioncosh2+sinh2=e2+e−22+e2−e−22=e2.{\cos h}2 + {\sin h}2 = \frac{e^{2} + e^{- 2}}{2} + \frac{e^{2} - e^{- 2}}{2} = e^{2}.cosh2+sinh2=2e2+e−2+2e2−e−2=e2.