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Question

Question: \[{\cos h}2 + {\sin h}2 =\]...

cosh2+sinh2={\cos h}2 + {\sin h}2 =

A

1e\frac{1}{e}

B

ee

C

1e2\frac{1}{e^{2}}

D

e2e^{2}

Answer

e2e^{2}

Explanation

Solution

cosh2+sinh2=e2+e22+e2e22=e2.{\cos h}2 + {\sin h}2 = \frac{e^{2} + e^{- 2}}{2} + \frac{e^{2} - e^{- 2}}{2} = e^{2}.