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Question

Question: \[{\cos h}^{- 1}x =\]...

cos⁡h−1x={\cos h}^{- 1}x =

A

log⁡(x+x2+1)\log(x + \sqrt{x^{2} + 1)}

B

log⁡(x−x2+1)\log(x - \sqrt{x^{2} + 1})

C

log⁡(x−x2−1)\log(x - \sqrt{x^{2} - 1})

D

log⁡(x+x2−1)\log(x + \sqrt{x^{2} - 1})

Answer

log⁡(x+x2−1)\log(x + \sqrt{x^{2} - 1})

Explanation

Solution

It is obvious.