cos(90°-θ) sin (90°-θ)= | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

cos(90°-θ) sin (90°-θ)=

A

$\frac{tanθ}{1-tan^2θ}$

B

$\frac{tanθ}{1+tan^2θ}$

C

1

D

0

Answer

$\frac{tanθ}{1+tan^2θ}$

Explanation

Solution

The correct option is (B): $\frac{tanθ}{1+tan^2θ}$