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Question

Mathematics Question on Trigonometric Functions

cos21+cos220+cos230+...+cos290\cos^2 \, 1^\circ + cos^2 2^0 + cos^2 \, 3^0 + ... + \cos^2 \, 90^\circ =

A

0

B

1

C

45

D

892\frac{89}{2}

Answer

892\frac{89}{2}

Explanation

Solution

If (A+B)=90(A + B) = 90^\circ then (cos2A+cos2B)=1(\cos^2 \, A+ \cos^2 \, B) = 1