Question
Mathematics Question on Trigonometric Functions
cos21∘+cos220+cos230+...+cos290∘ =
A
0
B
1
C
45
D
289
Answer
289
Explanation
Solution
If (A+B)=90∘ then (cos2A+cos2B)=1
cos21∘+cos220+cos230+...+cos290∘ =
0
1
45
289
289
If (A+B)=90∘ then (cos2A+cos2B)=1