QuestionReportMathematics Question on Inverse Trigonometric Functionscos−1(5−14)=\cos^{-1} ( \frac{\sqrt{5} -1}{4} ) = cos−1(45−1)=A3π10\frac{3 \pi}{10}103πB2π5\frac{2 \pi}{5}52πCπ5\frac{ \pi}{5}5πDπ15\frac{\pi}{15}15πAnswer2π5\frac{2 \pi}{5}52πExplanationSolution5−14=cos72∘\frac{\sqrt{5} -1}{4} = \cos 72^{\circ}45−1=cos72∘