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Question

Chemistry Question on Surface Chemistry

Correct equation of Freundlich isotherm is

A

log(mx)=logk+1nlogc\log \left(\frac{m}{x}\right)=\log k+\frac{1}{n} \log c

B

log(xm)=logc+1nlogk\log \left(\frac{x}{m}\right)=\log c+\frac{1}{n} \log k

C

log(xm)=logc+1klogc\log \left(\frac{x}{m}\right)=\log c+\frac{1}{k} \log c

D

log(xm)=logk+1klogc\log \left(\frac{x}{m}\right)=\log k+\frac{1}{k} \log c

Answer

log(mx)=logk+1nlogc\log \left(\frac{m}{x}\right)=\log k+\frac{1}{n} \log c

Explanation

Solution

The empirical relation, viz.,xm=kc1/nviz., \frac{x}{m}=kc^{1/n}, put forward by Freundlich is known as Freundlich's adsorption isotherm. Taking log on both sides log(xm)=logk+1nlogc\left(\frac{x}{m}\right)= \log \,k+\frac{1}{n} \log \,c