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Question

Physics Question on Fluid Mechanics

Correct Bernoulli's equation is (symbols have their usual meaning):

A

P+mgh+12mv2=constantP + mgh + \frac{1}{2} mv^2 = \text{constant}

B

P+ρgh+12ρv2=constantP + \rho gh + \frac{1}{2} \rho v^2 = \text{constant}

C

P+ρgh+ρv2=constantP + \rho gh + \rho v^2 = \text{constant}

D

P+12ρgh+12ρv2=constantP + \frac{1}{2} \rho gh + \frac{1}{2} \rho v^2 = \text{constant}

Answer

P+ρgh+12ρv2=constantP + \rho gh + \frac{1}{2} \rho v^2 = \text{constant}

Explanation

Solution

Bernoulli’s equation for fluid flow is:

P+ρgh+12ρv2=constant.P + \rho gh + \frac{1}{2} \rho v^2 = \text{constant}.

Here:
P is the pressure,
ρ\rho is the density of the fluid,
g is the acceleration due to gravity,
h is the height,
v is the velocity.

Final Answer: P+ρgh+12ρv2=constant.P + \rho gh + \frac{1}{2} \rho v^2 = \text{constant}.