Question

Copper has face centered cubic (fcc) lattice with interatomic spacing equal to 2.54Å. The value of the lattice constant for this lattice is.

• A. 1.27 Å
• B. 5.08 Å
• C. 2.54 Å
• D. 3.59 Å

Answer 1

Answer: (D)

3.59 Å

Answer 2

$\sqrt{2}a = 4r$⇒ $a = \frac{4r}{\sqrt{2}} = \sqrt{2}(2r) = \sqrt{2} \times 2.54 = 3.59Å$