Solveeit Logo
Login

Question

Chemistry Question on coordination compounds

Coordination number of Cr is six. A complex ion of Cr with C2O42−C_2O_4^{ 2-}, en and superoxide ion, O2−O_2^ - has the formula [Cr(C2O4)x(en)y(O2)z]−[Cr(C_2O_4)_x(en)_y(O_2)_z]^-. The ratio x : y : z will be

A

1:01:01

B

1:01:02

C

1:02:02

D

2:01:01

Answer

1:01:02

Explanation

Solution

x : y : z should be such that total charge = -1(i.e. charge on the complex ion). For (a), total charge = + 3 + 1 (-2) + 1(0) + 1 (-1) = 0 For (b), total charge = + 3 + 1 (-2) + 1(0) + 2(-1) = -1 Hence, (b) is correct.