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Question: Convert the following temperatures to the Kelvin scale. (a) \[25^\circ C\] (b) \[373^\circ C\]...

Convert the following temperatures to the Kelvin scale.
(a) 25C25^\circ C
(b) 373C373^\circ C

Explanation

Solution

Water freezes at 273.15K273.15\,{\text{K}} and boils at 373.15K373.15\,{\text{K}}. On the Celsius scale, water freezes at 0C0^\circ Cand boils at 100C100^\circ C. Therefore, we can say that 273.15K273.15\,{\text{K}} represents 0C0^\circ C on Celsius scale. Therefore, for each degree rise in temperature, there is a rise of 273 K in the Kelvin scale.

Formula used:
TK=TC0+273.15{T_K} = T_C^0 + 273.15
Here, TK{T_K} is the temperature in Kelvin and TC0T_C^0 is the temperature in Celsius.

Complete step by step solution:
We know that on the Kelvin scale, water freezes at 273.15K273.15\,{\text{K}} and boils at 373.15K373.15\,{\text{K}}. On the Celsius scale, water freezes at 0C0^\circ Cand boils at 100C100^\circ C. Therefore, we can say that 273.15K273.15\,{\text{K}} represents 0C0^\circ C on Celsius scale.From the above discussion, we can write,
TK=TC0+273.15{T_K} = T_C^0 + 273.15
Here, TK{T_K} is the temperature in Kelvin and TC0T_C^0 is the temperature in Celsius.

(a) 25C25^\circ C
We can use the above formula to convert 25C25^\circ C into Kelvin as follows,
TK=TC0+273.15{T_K} = T_C^0 + 273.15
Substituting 25C25^\circ C for TC0T_C^0 in the above equation, we get,
TK=25+273.15{T_K} = 25 + 273.15
TK=298.15K\therefore {T_K} = 298.15\,{\text{K}}

Therefore, the temperature 25C25^\circ C on the Kelvin scale is 298.15 K.

(b) 373C373^\circ C
We can use the above formula to convert 373C373^\circ C into Kelvin as follows,
TK=TC0+273.15{T_K} = T_C^0 + 273.15
Substituting 373C373^\circ C for TC0T_C^0 in the above equation, we get,
TK=373+273.15{T_K} = 373 + 273.15
TK=646.15K\therefore {T_K} = 646.15\,{\text{K}}

Therefore, the temperature 373C373^\circ C on the Kelvin scale is 646.15 K.

Additional information:
The Kelvin temperature is never negative. You may wonder why Kelvin starts from 273.15 K and not from 0 K. The lowest temperature recorded on the earth is 273.15C - 273.15^\circ {\text{C}}. Since the Kelvin temperature cannot be negative, 273.15 K is added to273.15C - 273.15^\circ {\text{C}}. Therefore, 273.15C+273.15K=0K273.15^\circ {\text{C}} + 273.15\,{\text{K}} = 0\,{\text{K}}. Therefore, the Kelvin always starts from 273.15 K to express the lowest temperature point on Celsius scale.

Note: Students must be aware not to confuse between the formula for converting Celsius temperature to Kelvin temperature and Celsius temperature to Fahrenheit temperature. You can avoid the number after the decimal to express the temperature in Kelvin scale. For example if the temperature is 273.15 K then you can write it as 273 K because figures after decimal point may create difficulties while doing calculations.