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Question

Question: Convert the following into basic units: (a) 28.7pm (b) 15.15pm (c) 25365mg...

Convert the following into basic units:
(a) 28.7pm
(b) 15.15pm
(c) 25365mg

Explanation

Solution

The question is asking us to convert the given units in terms of basic units like meters or grams. The units given in question are picometres and milligrams. Think about the conversion factors of picometres to meters and milligrams to grams. Then just calculate accordingly and get the answers.

Complete step by step solution:
- Let’s take a look at the question. It says, we need to convert the given units into basic units, that is, meters or grams.
- There are three values given in the question. Two of them are in terms of picometres (pm) and one is given in milligrams (mg).
- The term ‘pico-’ indicates 1012{{10}^{-12}} and the term ‘milli-’ indicates 103{{10}^{-3}}.
- We know that, 1pm=1012m1pm={{10}^{-12}}m.
- Therefore, 28.7pm=28.7×1012m28.7pm=28.7\times {{10}^{-12}}m.
- Similarly, 15.15pm=15.15×1012m15.15pm=15.15\times {{10}^{-12}}m.
- Now, let’s move on to the third value which is given in milligrams.
- We know that, 1mg=103g1mg={{10}^{-3}}g.
- Therefore, 25365mg=25365×103g=25.365g25365mg=25365\times {{10}^{-3}}g=25.365g.

- Hence,
(a) 28.7pm=28.7×1012m28.7pm=28.7\times {{10}^{-12}}m
(b) 15.15pm=15.15×1012m15.15pm=15.15\times {{10}^{-12}}m
(c) 25365mg=25365×103g=25.365g25365mg=25365\times {{10}^{-3}}g=25.365g

Additional information:
Here are some conversion factors.
1dm=101m1dm={{10}^{-1}}m
1cm=102m1cm={{10}^{-2}}m
1mm=103m1mm={{10}^{-3}}m
1μm=106m1\mu m={{10}^{-6}}m
1nm=109m1nm={{10}^{-9}}m
1Ao=1010m1{{A}^{o}}={{10}^{-10}}m
1pm=1012m1pm={{10}^{-12}}m
These are some of the conversion factors. The conversion factors will remain the same for all the basic units like grams and litres as well.

Note: Remember some of the important conversion factors as they are useful while solving problems. The factors listed above are of decimal scale. There are more factors in ascending scales like kilo-, mega-, giga-, tera- and so on.