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Question

Question: Convert 3.6m into mm....

Convert 3.6m into mm.

Explanation

Solution

Convert the given value in the required specific units by using the conversion relation. Use the formula - 1m=103mm1m = {10^3}mm. Place the relation and simplify the equation using the basic mathematical calculations.

Complete step by step solution:
We know that the basic relation between metres and Millimetres.
1m=103mm1m = {10^3}mm
Place the value in the given value –
3.6m=3.6×103mm3.6m = 3.6 \times {10^3}mm
Simplify the above equation –
3.6m=3.6×1000  mm3.6m = 3.6 \times 1000\;mm
3.6m=3600 mm\therefore 3.6m = 3600{\text{ }}mm

Hence, 3.6 m is equal to 36000 mm.

Additional information:
In physics, the units are the standards for the measurement of the physical quantities which needs to be clear to be useful. Units are the internationally accepted standards for measurements of the physical quantities.Different types of system of units are –

SI (International system of units): The SI units are the standards of measurement defined by the international system of units. There are basic seven SI units which comprises of –Length – meter, Time – second, Amount of substance- mole, Electric current – Ampere, Temperature – Kelvin, Luminous intensity – candela and Mass - kilogram

MKS (Meter-kilogram-second) system: MKS system is the system of units, where length is measured in meters, mass in kilogram and time in seconds. Generally, MKS systems are used in engineering and in advanced physics.

CGS (centimetre-gram-second) system: CGS system is the system of units, where length is measured in centimeters, mass in grams and time in seconds. Generally, CGS systems are used in the theoretical studies of physics.

Note: It is very important to know the difference between the system of units and the conversional ratios between them. Since if we say mass of one it does not make any sense, also mass of one gram and one kilogram differs a lot as 1kg=1000g1kg = 1000g. Always check the units of the given term, all the given terms should be in the same system and then start solving. Also, remember the conversional relations of the different physical quantities and apply accordingly.