Question

Convert 1 - chloropropane into following:
A.$Propan - 1 - ol$
B.$1 - iodopropane$
C.Butane nitrile
D.Propyl ethanoate

Answer 1

Conversion: When a chemical reaction takes place, the process of converting takes place and some potion disappears and is converted to other products. The conversion of $1 - chloropropane$ into the following compounds are simple organic reactions. $1 - chloropropane$ (Also known as n-propyl chloride or$1 - propyl$ $chloride$) is an organic compound. The chemical formula for $1 - chloropropane$ is ${C_3}{H_7}Cl$.

Complete step by step solution:
When the $1 - chloropropane$ is reacted with alcoholic potassium hydroxide,$KOH$, to give the product $Propan - 1 - ol$, the chemical formula for $Propan - 1 - ol$ is ${C_3}{H_7}OH$ and potassium chloride,$KCl$, is the byproduct for this reaction.
We can write the chemical equation for this chemical reaction as,

Now we can discuss the conversion of $1 - chloropropane$ into $1 - iodopropane$.
Now we discuss the conversion of $1 - chloropropane$ into Butane nitrile.
$1 - chloropropane$ is reacted with sodium iodide,$NaI$, to give the corresponding product $1 - iodopropane$, (chemical formula: ${C_3}{H_7}I$) and also give sodium chloride,$NaCl$, as byproduct.
We can write the chemical equation for this chemical reaction as,

Now we can discuss the reaction of $1 - chloropropane$ with potassium cyanide,$KCN$, to give butane nitrile (chemical formula: ${C_4}{H_7}N$). And potassium chloride,$KCl,$ is eliminated.
We can write the chemical equation for this chemical reaction as,

Now we can discuss the conversion of $1 - chloropropane$ into Propyl ethanoate.
When the $1 - chloropropane$ is reacted with alcoholic potassium hydroxide,$KOH$, to give the product $Propan - 1 - ol$, the chemical formula for $Propan - 1 - ol$ is ${C_3}{H_7}OH$. And potassium chloride,$KCl$, is the byproduct for this reaction. Then $Propan - 1 - ol$ is treated with propionic acid, chemical formula-${C_3}{H_6}{O_2}$, to give the corresponding product Propyl ethanoate (chemical formula:${C_5}{H_{10}}{O_2}$), and eliminates water molecule.
We can write the chemical reaction for Conversion of $1 - chloropropane$ into Propyl ethanoate as,

Therefore, the option A and B is correct.

Note: All the above three conversions (options a, b and d) contain the same carbon atoms on both sides, reactant sides and product sides. But in option (c), Conversion of $1 - chloropropane$into Butane nitrile, that butane nitrile containing one carbon atom more than the reactant,$1 - chloropropane$.
$1 - chloropropane$ is used in pharmaceutical intermediate for $n - propylamine$ and solvent for making other chemicals which is also used in pesticides.